Grade 12 Physical Sciences
Term 3 · Weeks 7–8

Electrochemical Reactions

Paper 2Chemistry · Grade 12

Electrochemistry links chemistry and electricity. Spontaneous redox reactions in galvanic cells release electrical energy, while electrolytic cells use electrical energy to drive non-spontaneous reactions. The standard electrode potential table allows us to predict which reactions will occur and to calculate cell voltages.

Week 8

12.1 Galvanic Cells

Distinguish galvanic cells from electrolytic cellsDescribe and draw a galvanic cell (Zn-Cu example): anode = oxidation (−), cathode = reduction (+)Write half-reactions and overall cell equations

Definition

Galvanic cell

An electrochemical cell in which a spontaneous redox reaction produces electrical energy. The anode (negative electrode) undergoes oxidation; the cathode (positive electrode) undergoes reduction.

In a galvanic (voltaic) cell, two different metals are placed in separate electrolyte solutions connected by a salt bridge. The more reactive metal (e.g. zinc) loses electrons at the anode (oxidation). Electrons flow through the external circuit to the cathode (e.g. copper), where reduction occurs. The salt bridge maintains electrical neutrality by allowing ion movement between the two half-cells.

ZnSO₄ (aq)ZnZn→Zn²⁺+2e⁻(oxidation)CuSO₄ (aq)CuCu²⁺+2e⁻→Cu(reduction)Salt bridgee⁻ →Anode (−)Cathode (+)
Zn-Cu galvanic cell: zinc anode (negative, oxidation) in ZnSO₄ solution, copper cathode (positive, reduction) in CuSO₄ solution. Electrons flow from Zn to Cu through the external circuit. The salt bridge completes the circuit.

Zn-Cu galvanic cell half-reactions

  • Anode (oxidation): Zn(s) → Zn²⁺(aq) + 2e⁻
  • Cathode (reduction): Cu²⁺(aq) + 2e⁻ → Cu(s)
  • Overall: Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s)

Exam Tip

Memory aid: OIL RIG — Oxidation Is Loss (of electrons), Reduction Is Gain (of electrons). In a galvanic cell: ANODE = oxidation = negative; CATHODE = reduction = positive. In an electrolytic cell the signs flip — see Section 12.2.

Worked Example

A galvanic cell uses a magnesium anode and a silver cathode. Write (a) the half-reactions and (b) the overall cell equation.

Given

  • Anode metal: Mg
  • Cathode: Ag⁺/Ag

Find

Half-reactions and overall equation

Solution

  1. 1Anode (oxidation): Mg(s) → Mg²⁺(aq) + 2e⁻
  2. 2Cathode (reduction): Ag⁺(aq) + e⁻ → Ag(s) — balance electrons: multiply by 2
  3. 3Balanced cathode: 2Ag⁺(aq) + 2e⁻ → 2Ag(s)
  4. 4Overall: Mg(s) + 2Ag⁺(aq) → Mg²⁺(aq) + 2Ag(s)
Answer: Anode: Mg → Mg²⁺ + 2e⁻; Cathode: 2Ag⁺ + 2e⁻ → 2Ag; Overall: Mg + 2Ag⁺ → Mg²⁺ + 2Ag
?

Practice Question

A galvanic cell is constructed with a zinc electrode in ZnSO₄ and an iron electrode in FeSO₄. Using the EMF series (E°Zn²⁺/Zn = −0.76 V; E°Fe²⁺/Fe = −0.44 V), identify which electrode is the anode, which is the cathode, and write the half-reactions.

(6 marks)

Watch Out

Common mistake: writing the anode half-reaction as a reduction. The anode ALWAYS undergoes oxidation (electrons are produced). The cathode ALWAYS undergoes reduction (electrons are consumed).

Week 9

12.2 Electrolytic Cells and Standard Electrode Potentials

Describe and draw an electrolytic cell: anode = oxidation (+), cathode = reduction (−)Use the standard electrode potential table (EMF series) to predict cell reactionsCalculate standard emf: E°cell = E°cathode − E°anode

Definition

Electrolytic cell

An electrochemical cell in which an external electrical source drives a non-spontaneous redox reaction.

Definition

Standard electrode potential

The potential difference measured under standard conditions (1 mol·dm⁻³, 25°C, 100 kPa) relative to the standard hydrogen electrode.

Electrolyte solutionCathodeReduction+AnodeOxidationBattery (DC)← e⁻e⁻ →External EMF drives non-spontaneous reaction
Electrolytic cell: an external battery forces current through an electrolyte. The anode (connected to + terminal) undergoes oxidation; the cathode (connected to − terminal) undergoes reduction. Example: electrolysis of copper sulfate solution.

In an electrolytic cell, the external power supply forces current in a direction opposite to that which would occur spontaneously. The electrode connected to the positive terminal of the supply is the anode (oxidation occurs). The electrode connected to the negative terminal is the cathode (reduction occurs). Note: in electrolytic cells the anode is positive and the cathode is negative — the opposite of a galvanic cell.

Galvanic Cell vs Electrolytic Cell

PropertyGalvanic CellElectrolytic Cell
Energy conversionChemical → electricalElectrical → chemical
Reaction typeSpontaneous redoxNon-spontaneous redox
Anode signNegative (−)Positive (+)
Cathode signPositive (+)Negative (−)
External supplyNot required — cell produces voltageRequired — external battery drives reaction
E°cellPositive (spontaneous)Negative (non-spontaneous)
ExampleZn-Cu Daniell cell, car batteryElectroplating, water electrolysis

Formula

Standard cell emf

Ecell=EcathodeEanode\mathcal{E}_{cell} = \mathcal{E}_{cathode} - \mathcal{E}_{anode}

E°cell = standard cell emf (V), E°cathode = standard reduction potential of cathode (V), E°anode = standard reduction potential of anode (V)

SI unit: V

Exam Tip

Using the EMF table: the electrode with the higher (more positive) standard reduction potential is the cathode. The electrode with the lower (more negative) standard reduction potential is the anode. A positive E°cell means the reaction is spontaneous (galvanic). A negative E°cell means it is non-spontaneous (electrolytic).

Worked Example

Calculate the standard cell emf for a galvanic cell with a zinc anode and a copper cathode. (E°Zn²⁺/Zn = −0.76 V; E°Cu²⁺/Cu = +0.34 V). Is the reaction spontaneous?

Given

  • E°cathode (Cu²⁺/Cu) = +0.34 V
  • E°anode (Zn²⁺/Zn) = −0.76 V

Find

E°cell

Solution

  1. 1E°cell = E°cathode − E°anode = (+0.34) − (−0.76) = 0.34 + 0.76 = 1.10 V
  2. 2E°cell = +1.10 V (positive → spontaneous reaction ✓)
Answer: E°cell = +1.10 V. The reaction is spontaneous — this is a galvanic cell.
?

Practice Question

Using the standard electrode potentials: E°(Pb²⁺/Pb) = −0.13 V and E°(Sn²⁺/Sn) = −0.14 V. (a) Identify which is the anode and which is the cathode in a galvanic cell. (b) Calculate E°cell. (c) Write the overall cell equation.

(6 marks)

Watch Out

Common mistake: reversing the formula as E°cell = E°anode − E°cathode. Always use E°cell = E°cathode − E°anode. The cathode value comes first. If you get a negative answer for what should be a galvanic cell, you have the electrodes the wrong way around.

Week 10

12.3 Practical Applications: Electroplating and Rechargeable Cells

Describe practical applications: electroplating, rechargeable cellsWrite half-reactions and overall cell equations

Electroplating is a practical application of electrolysis. An electrolytic cell is used to deposit a thin layer of one metal onto another. The object to be plated is made the cathode (reduction occurs, metal deposits). The plating metal (e.g. copper, silver, gold) is made the anode — it dissolves to replenish the electrolyte. The electrolyte contains ions of the plating metal.

Electroplating setup (copper plating example)

  1. Cathode: the object to be plated (e.g. iron spoon) — connected to − terminal
  2. Anode: pure copper plate — connected to + terminal, dissolves slowly
  3. Electrolyte: copper sulfate solution (CuSO₄)
  4. Cathode half-reaction: Cu²⁺(aq) + 2e⁻ → Cu(s) — copper deposits on object
  5. Anode half-reaction: Cu(s) → Cu²⁺(aq) + 2e⁻ — copper anode dissolves
🌍

Real World

Electroplating applications: chrome plating on car bumpers (corrosion resistance), gold plating on jewellery and electronics (conductivity and aesthetics), silver plating on cutlery. Galvanising (coating steel with zinc) uses a similar process to protect steel from rusting.

Rechargeable cells (secondary cells) can be recharged by reversing the current. The lead-acid battery in a car is a classic example. During discharge (galvanic mode), lead is oxidised at the anode and lead dioxide is reduced at the cathode. During charging (electrolytic mode), the reactions are reversed. Lithium-ion batteries in phones and laptops work on the same principle — intercalation of lithium ions.

Primary vs Secondary (Rechargeable) Cells

PropertyPrimary CellSecondary Cell
RechargeabilityCannot be recharged — discarded when flatCan be recharged many times
ModeGalvanic onlyGalvanic (discharge) and electrolytic (charge)
ExamplesAlkaline AA battery, zinc-carbon cellLead-acid car battery, Li-ion phone battery
CostLower initial costHigher initial cost but cheaper long-term
Environmental impactMore waste (disposable)Less waste (reusable)

Worked Example

During the charging of a lead-acid battery the following reaction occurs at the cathode: PbSO₄(s) + 2e⁻ → Pb(s) + SO₄²⁻(aq). (a) Is this cell now acting as a galvanic or electrolytic cell? (b) Is the cathode connected to the positive or negative terminal of the external charger?

Given

  • Cathode reaction (charging): PbSO₄ + 2e⁻ → Pb + SO₄²⁻

Find

Cell type and terminal polarity

Solution

  1. 1During charging, an external electrical source drives the reaction → electrolytic cell.
  2. 2Reduction occurs at the cathode in an electrolytic cell.
  3. 3In an electrolytic cell, the cathode is connected to the negative (−) terminal of the external supply.
Answer: The cell acts as an electrolytic cell during charging. The cathode is connected to the negative (−) terminal of the charger.
?

Practice Question

Describe the process of silver electroplating of a copper spoon. In your answer identify the anode, cathode, and electrolyte, and write the cathode half-reaction.

(5 marks)

?

Practice Question

A galvanic cell produces a current of 0.5 A for 2 hours. Calculate the charge transferred. (Q = It)

(3 marks)

Exam Tip

Exam tip: If a question asks you to compare a galvanic cell and an electrolytic cell, always address these four points: (1) energy conversion direction, (2) spontaneity of reaction, (3) sign of anode, (4) sign of cathode. Four points = four marks.

Watch Out

Do not confuse the salt bridge in a galvanic cell with the electrolyte in an electrolytic cell. They serve different purposes: the salt bridge maintains charge balance between two separate half-cells; the electrolyte in an electrolytic cell is a single solution through which ions carry the current.

Electrochemical Reactions Grade 12 Physical Sciences CAPS Notes | MathSciBuddy