Surface Area & Volume
We calculate the surface area and volume of prisms, pyramids, cylinders, and spheres. We investigate how changing dimensions affects volume and solve real-world problems involving capacity and packaging.
10.1 Surface Area of 3D Objects
- Calculate the total surface area of prisms (including cylinders)
- Calculate the total surface area of pyramids (including cones)
- Solve problems involving surface area in real-world contexts
Real-World Connection
Surface area determines how much paint, wrapping, or material is needed to cover an object. A painter calculates the surface area of walls and ceilings. A car manufacturer calculates the surface area of body panels to determine paint cost. A food company designs packaging by minimising surface area (material cost) while maintaining a fixed volume (product capacity).
Surface Area Formulae
Solid
Total Surface Area
Rectangular prism
2(lw + lh + wh)
Cylinder (closed)
2πr² + 2πrh = 2πr(r + h)
Square pyramid
b² + 2bl (b = base, l = slant height)
Cone (closed)
πr² + πrl = πr(r + l)
Sphere
4πr²
💡 Tip
For an OPEN container (no lid), subtract one base from the total surface area formula. For a cone without a base, use πrl only.
Worked Example
Surface area of a cylinder
Problem
Worked Example
Surface area of a rectangular prism
Problem
Worked Example
Surface area of a square pyramid
Problem
CAPS Cognitive Level Distribution
10.2 Volume of 3D Objects
- Calculate the volume of prisms and cylinders
- Calculate the volume of pyramids, cones, and spheres
- Investigate the effect of doubling dimensions on volume
- Solve problems in context
Real-World Connection
Volume determines how much a container holds — capacity. A water tank's volume tells you how many litres it holds. A moving company calculates the cubic metres of furniture to determine how many trucks are needed. The volume of a medicine capsule determines the drug dosage. Volume calculations are essential in engineering, medicine, and manufacturing.
Volume Formulae
Solid
Volume
Rectangular prism
V = l × w × h
Cylinder
V = πr²h
Pyramid (any base)
V = ⅓ × base area × height
Cone
V = ⅓πr²h
Sphere
V = ⁴⁄₃πr³
ℹ️ Note
1 litre = 1000 cm³ = 1 dm³. This conversion is frequently used when problems involve capacity (litres) rather than cubic centimetres.
Property / Rule
Effect of Scaling on Volume
If all dimensions are multiplied by factor k, volume multiplies by k³. Doubling all dimensions (k=2) gives 8× the volume.
Worked Example
Volume of a composite solid
Problem
Worked Example
Effect of doubling dimensions on volume
Problem
Worked Example
Volume of a triangular prism
Problem
CAPS Cognitive Level Distribution